A steady current 'l' flows in a small square loop of wire of side L in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let 
and 
respectively denote the magnetic moments of the current loop before and after folding. Then:
A
= 0
B
and 
are in the same direction
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
(c ) µ 1 = L 2
µ 2 = 
× L × 
µ 2 = 
= 
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